4^x+^2=12

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Solution for 4^x+^2=12 equation: 



4^x+^2=12

We move all terms to the left:

4^x+^2-(12)=0

determiningTheFunctionDomain
4^x-12+^2=0

We add all the numbers together, and all the variables

4^x=0

x=0/1

x=0

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